Primary Ideals, Finitely Many Saturations

Finitely Many Saturations

Let J be a proper ideal and assume a primary decomposition for J. Thus J is the intersection of primary ideals Hi, below primes Pi.

If T is a multiplicatively closed set containing 1, what can we say about the saturation of J with respect to T?

Look at J as an intersection. Some u drives x into J iff it drives x into each Hi. In other words, saturation commutes with intersection. Find the saturation of each Hi with respect to T, and take their intersection.

If Hi is Pi primary, ask whether T intersects Pi. If they intersect in u, a power of u winds up in Hi, T intersects Hi, and the saturation is all of R.

If T and Pi do not intersect, ratchet T up to the complement of Pi, which can only make the saturation larger. (Since T contains 1, the saturation is at least Hi.) Now Pi is minimal over Hi, and the saturation through the complement of Pi gives the smallest primary ideal between Hi and Pi. This has to be Hi. Thus the saturation of Hi with respect to T yields Hi.

Everything depends on whether T intersects Pi. The saturation of J becomes the intersection of some of the primes in σ(J), specifically, those primes that miss T.

There are finitely many cases, finitely many ways to miss some of the primes in σ(J). If σ(J) has n primes, there are at most 2n different saturations of J.

Sometimes it is helpful to change T in some way. As long as T intersects the same prime ideals in σ(J), the saturation has not changed.