Build E by placing the variable x down the main diagonal, and subtracting T. As you recall, the determinant of E gives the characteristic polynomial for T.
Let F be the adjoint of E. Thus E*F gives the determinant, which we will call p(x).
Write F as F0 + F1 + F2 + … Fn, where Fi retains only the coefficients on xi. Thus F0 is a matrix based on the constants of F, Fn-1 is the identity matrix, and Fn is 0, since no cofactors produce xn.
Now E*F becomes x-T times the sum over Fixi, while p is the sum of its terms. If ci is the ith coefficient on p, we can write ci = Fi-1-TFi.
Premultiply the ith equation by Ti. For example, equation3 becomes:
T3c3 = T3F2 - T4F3
Add these equations together and the right side telescopes to -TnFn, which is 0. The left side becomes p(T). Therefore p(T) = 0, and T is a root of its characteristic polynomial.
Convert T to jordan form, and find its minimum polynomial m(x), as described in the previous section. This is the lcm of the minimum polynomials of the jordan blocks.
Let a block be diagonal, with eigen value l. Its minimum polynomial is x-l, which is a factor of its characteristic polynomial (x-l)b, where b is the size of the block.
Next consider a jordan block with l down the diagonal and ones on the subdiagonal. Once again the characteristic polynomial is (x-l)b. Replace x with the jordan block and evaluate. The expression x-l eaves only the subdiagonal, and when this is raised to the b power, the result is 0.
Each block satisfies its characteristic bpolynomial, and the product of these polynomials gives the characteristic polynomial for T, which is satisfied by all the blocks of T, and by T itself.