Let a and b be two Cauchy sequences taken from T. Let d(a,b) be the sequence dj = |aj,bj|. Given ε, choose n so that both tails are within ε of an and bn respectively. Now dj is within 2ε of dn. In other words, d is a Cauchy sequence of real numbers. Since the reals are complete, this is a real number. Let this be the distance between a and b.
Verify that the triangular inequality holds; it is inherited from S. And the distance from a to b is the distance from b to a. Thus we have a valid pseudo metric. Turn T into a proper metric space by clumping equivalent sequences together. In other words, alll sequences that are distance 0 apart become one point. We did the same thing for the reals. The result is a metric space, the completion of S.
Is T a complete metric space? It is, using the same proof as the reals. The completion of any metric space is complete.